If it's not what You are looking for type in the equation solver your own equation and let us solve it.
-8x^2+32x+10=2.5x+4
We move all terms to the left:
-8x^2+32x+10-(2.5x+4)=0
We get rid of parentheses
-8x^2+32x-2.5x-4+10=0
We add all the numbers together, and all the variables
-8x^2+29.5x+6=0
a = -8; b = 29.5; c = +6;
Δ = b2-4ac
Δ = 29.52-4·(-8)·6
Δ = 1062.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29.5)-\sqrt{1062.25}}{2*-8}=\frac{-29.5-\sqrt{1062.25}}{-16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29.5)+\sqrt{1062.25}}{2*-8}=\frac{-29.5+\sqrt{1062.25}}{-16} $
| f(9f-4)=0 | | 4(x+3)=3(x+12) | | 3x−9+15x=18x-9 | | (v-3)(v+6)=0 | | 3x+14=7x-14 | | -4x+3=75+5x | | c(c-3)=0 | | (w+1)(w-5)=0 | | 4x2−5x−6=0 | | 24x^2-82x+48=0 | | 5x-6=3+6x | | (s-4)(s+9)=0 | | (q-6)(q+4)=0 | | 3x10=5(x+12) | | (r-5)(r+6)=0 | | (r-5)(r+6)=6 | | .50p+3=8 | | 20=3×w | | 4+2p=10(1/5p-2) | | w+4=24 | | 5a-10=4a-+8 | | -15+2x=5(-3-5x | | q^2-40q+820=0 | | w−w+w+3w−w=15 | | 2x+2x+6+4=-14 | | x+8x-9=18 | | 2(3x+1)+4=36 | | 8x-23=8x+191 | | 62-y=292 | | 4(2y-7)=44 | | 2x+4(x-9)=114 | | X+2x+3-x=2x1 |